2y^2-4y+7=0

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Solution for 2y^2-4y+7=0 equation:


Simplifying
2y2 + -4y + 7 = 0

Reorder the terms:
7 + -4y + 2y2 = 0

Solving
7 + -4y + 2y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
3.5 + -2y + y2 = 0

Move the constant term to the right:

Add '-3.5' to each side of the equation.
3.5 + -2y + -3.5 + y2 = 0 + -3.5

Reorder the terms:
3.5 + -3.5 + -2y + y2 = 0 + -3.5

Combine like terms: 3.5 + -3.5 = 0.0
0.0 + -2y + y2 = 0 + -3.5
-2y + y2 = 0 + -3.5

Combine like terms: 0 + -3.5 = -3.5
-2y + y2 = -3.5

The y term is -2y.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2y + 1 + y2 = -3.5 + 1

Reorder the terms:
1 + -2y + y2 = -3.5 + 1

Combine like terms: -3.5 + 1 = -2.5
1 + -2y + y2 = -2.5

Factor a perfect square on the left side:
(y + -1)(y + -1) = -2.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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